Well so you can do ds.foo instead of having to do ds[DataSource.Foo]. This is something Markus wanted.
-- Siegfried-Angel Gevatter Pujals (RainCT) Free Software Developer 363DEAE3
Well so you can do ds.foo instead of having to do ds[DataSource.Foo].
This is something Markus wanted.
--
Siegfried-Angel Gevatter Pujals (RainCT)
Free Software Developer 363DEAE3